2x^2-3x-35=x^2-x

Solution for 2x^2-3x-35=x^2-x equation:

2x^2-3x-35=x^2-x

We move all terms to the left:

2x^2-3x-35-(x^2-x)=0

We get rid of parentheses

2x^2-x^2-3x+x-35=0

We add all the numbers together, and all the variables

x^2-2x-35=0

a = 1; b = -2; c = -35;
Δ = b2-4ac
Δ = -22-4·1·(-35)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-12}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+12}{2*1}=\frac{14}{2}
=7
$